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3v^2-3v-80=0
a = 3; b = -3; c = -80;
Δ = b2-4ac
Δ = -32-4·3·(-80)
Δ = 969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{969}}{2*3}=\frac{3-\sqrt{969}}{6} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{969}}{2*3}=\frac{3+\sqrt{969}}{6} $
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